使用 .andThrough() 时发生类型推断错误
作者: msickpaler创建于 2025年11月4日更新于 2026年3月4日
Curiously, if I comment out .andThen((s) => ok(s)), the error disappears and the return type becomes exactly as expected.
内容来源: supermacro/neverthrow
Curiously, if I comment out .andThen((s) => ok(s)), the error disappears and the return type becomes exactly as expected.
内容来源: supermacro/neverthrow