[BUG]: templated 构造函数的 implicitly_convertible
作者: jeanchristopheruel创建于 2024年7月26日更新于 2026年6月23日
标签triage
The Python binding:
PYBIND11_MODULE(example, m) {
py::class_<A>(m, "A")
.def("print", &A::print);
py::class_<B>(m, "B")
.def(py::init<>())
.def("print", &B::print);
py::class_<C>(m, "C")
.def(py::init<>())
.def("print", &C::print);
py::implicitly_convertible<B, A>();
py::implicitly_convertible<C, A>();
m.def("print", &print);
}I would expect the Python binding to behave like:
import example
b = example.B()
print_from_b = example.print(b) # This should print "I am B" due to implicit conversion
c = example.C()
print_from_c = example.print(c) # This should print "I am C" due to implicit conversion内容来源: pybind/pybind11