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EasyHttp

> 编程语言
开源

适用于 C# 的 HTTP 库

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工具介绍

适用于 C# 的 HTTP 库

Project Status

This project is active and maintained by David Alpert.

EasyHttp

An easy to use HTTP client that supports:

  • HEAD, PUT, DELETE, GET, POST
  • Cookies
  • Authentication
  • Dynamic and Static Typing
  • XML, JSON and WWW-Url form encoded encoding/decoding
  • File upload both via PUT and POST (multipart/formdata)
  • Some other neat little features....

License

Licensed under Modified BSD (i.e. pretty much MIT).

For full License and included software licenses please see LICENSE.TXT

Please log all issues here: http://youtrack.codebetter.com/issues/EHTTP

Installation

You can either download the source and compile or use nuget at http://nuget.org. To install with nuget:

Install-Package EasyHttp

Documentation

The documentation can be found on the wiki.

Usage

Using static types

To post/put a customer to some service:

	var customer = new Customer(); 
	customer.Name = "Joe"; 
	customer.Email = "[email protected]";
	var http = new HttpClient();
	http.Post("url", customer, HttpContentTypes.ApplicationJson);

To get some data in JSON format:

	var http = new HttpClient();
	http.Request.Accept = HttpContentTypes.ApplicationJson;
	var response = http.Get("url");
	var customer = response.StaticBody();
	Console.WriteLine("Name: {0}", customer.Name);

Using dynamic types

To post/put a customer to some service:

	var customer = new ExpandoObject(); // Or any dynamic type
	customer.Name = "Joe";
	customer.Email = "[email protected]";
	var http = new HttpClient();
	http.Post("url", customer, HttpContentTypes.ApplicationJson);

To get some data in JSON format:

	var http = new HttpClient();
	http.Request.Accept = HttpContentTypes.ApplicationJson;
	var response = http.Get("url");
	var customer = response.DynamicBody;
	Console.WriteLine("Name {0}", customer.Name);

Both in Static and Dynamic versions, hierarchies are supported.

Perform a get with parameters

To get some data from a service

var http = new HttpClient();
http.Get("url", new {Name = "test"});

Should translate to the following url being passed. url?Name=test the value will be urlencoded.

To get some data in JSon format.

var http = new HttpClient();
http.Request.Accept = HttpContentTypes.ApplicationJson;
http.Get("url", new {Name = "test"});

Serialization / Deserialization Conventions

For serialization / deserialization, you can use pretty much any type of naming convention, be it Propercase, CamelCase, lowerCamelCase, with_underscores, etc. If for some reason, your convention is not picked up, you can always decorate the property with an attribute:

 
   [JsonName("mycustomname")] 
   public string SomeWeirdCombination { get; set; }

Credits

Copyright (c) 2010 - 2017 Hadi Hariri and Project Contributors

JsonFX: Licensed under MIT. EasyHttp uses the awesome JsonFX library at http://github.com/jsonfx

Issues· 0 开放

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C#

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> 工具信息

发布日期2026年8月1日
最后更新2026年9月17日
分类编程语言
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