Deadlock when using nested tasks + semaphore

TEST_CASE("LazyInit_Deadlocks.16threads")
{
	using namespace std::chrono_literals;

	for (size_t i = 0; i < 10000; ++i)
	{
		//std::cout << i << std::endl;
		tf::Executor executor(16);
		tf::Semaphore semaphore(1);
		std::atomic_bool has_value = false;
		
		// The following lambda simulates lazy initializer of some complex and slow to initialize variable
		auto lazy_data = [&]()
		{
			// If we already have a value, return it
			if (!has_value.load(std::memory_order_acquire))
			{
				// Otherwise, calculate it in a task
				tf::Taskflow taskflow2;
				// Let's imagine the following task is just some slow and complex initialization of some meaningful variable
				auto task = taskflow2.emplace([&]() {
					if (!has_value.load(std::memory_order_acquire))
					{
						tf::Taskflow taskflow3;
						taskflow3.emplace([&] { std::this_thread::sleep_for(1ms); });
						executor.corun(taskflow3);
						has_value.store(true, std::memory_order_release);
					}
					});
				task.acquire(semaphore);
				task.release(semaphore);
				executor.corun(taskflow2);
			}
			return 99;
		};

		tf::Taskflow taskflow1;
		for (size_t k = 0; k < 16; ++k)
		{
			taskflow1.emplace(
				[&]
				{
					lazy_data();
				});
		}

		// If the following line fails - you are expiriencing deadlock
		REQUIRE(executor.run(taskflow1).wait_for(5s) == std::future_status::ready);
	}
}