Output base dir content without `./` prefix when multiple search paths are used

What version of fd are you using? fd 10.5.0

Is it possible to have a fd call to return non-./-prefixed paths when "." and other search paths are passed?

Here's a minimal reproduce to highlight the problem:

mkdir -p a/b/c
touch a/fileA a/b/fileB a/b/c/fileC
fd -C a --type f --exclude b --search-path=. --search-path=b/c

result:

./fileA
b/c/fileC

I want all entries to be outputted without ./, so the desired result is:

fileA
b/c/fileC

but I can't pass empty search path to make this happen. If any of those can return the desired result, I'll be happy:

# allow empty search path
fd -C a --type f --exclude b --search-path= --search-path=b/c

# make --strip-cwd-prefix not fail when search paths are used
fd -C a --type f --exclude b --strip-cwd-prefix --search-path=. --search-path=b/c

# introduce a new flag to search in the base directory
fd -C a --type f --exclude b --search-base-directory --search-path=b/c

Why this feels like a bug/overlook: such call does not prepend ./:

fd -C a --type f --exclude b

but as soon as you list any search path, you're also forced to list "." as the search path:

fd -C a --type f --exclude b --search-path=. --search-path=b/c

and the way git ignores are applied, it requires the first search to point to the right directory (usually ".").

Any advice to make this work?

Thanks for the great tool!