#630·schedule

Schedules jobs too often if multiple threads are present

Author: KlimrothCreated Aug 1, 2024Updated Aug 10, 2024

If I schedule two jobs and each job should be run in one thread, the following minimal example does not work

`import schedule import threading import time from datetime import datetime

def do_task_1() -> None: print(f"{datetime.now().isoformat()} - task 1 execution - thread {threading.current_thread().name} \n")

def do_task_2() -> None: print(f"{datetime.now().isoformat()} - task 2 execution - thread {threading.current_thread().name} \n")

def task_1_sheduler() -> None: schedule.every(10).seconds.do(do_task_1) while True: time.sleep(1) schedule.run_pending()

def task_2_sheduler() -> None: schedule.every(14).seconds.do(do_task_2) while True: time.sleep(1) schedule.run_pending()

def start_thread_1() -> None: t = threading.Thread(target=task_1_sheduler) t.start()

def start_thread_2() -> None: t = threading.Thread(target=task_2_sheduler) t.start()

start_thread_1() start_thread_2() `

I would expect it to conduct do_task_2 every 14 seconds on thread 2 and do_task_1 independently every 10 seconds on thread 1, but it mixes things up

image001

What am I doing wrong?